(z+3)(z-7)=z^2-4z-21

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Solution for (z+3)(z-7)=z^2-4z-21 equation: 



(z+3)(z-7)=z^2-4z-21

We move all terms to the left:

(z+3)(z-7)-(z^2-4z-21)=0

We get rid of parentheses

-z^2+(z+3)(z-7)+4z+21=0

We multiply parentheses ..

-z^2+(+z^2-7z+3z-21)+4z+21=0

We add all the numbers together, and all the variables

-1z^2+(+z^2-7z+3z-21)+4z+21=0

We get rid of parentheses

-1z^2+z^2-7z+3z+4z-21+21=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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